.5x^2-4x+10=0

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Solution for .5x^2-4x+10=0 equation:


Simplifying
0.5x2 + -4x + 10 = 0

Reorder the terms:
10 + -4x + 0.5x2 = 0

Solving
10 + -4x + 0.5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
0.5 the coefficient of the squared term: 

Divide each side by '0.5'.
20 + -8x + x2 = 0

Move the constant term to the right:

Add '-20' to each side of the equation.
20 + -8x + -20 + x2 = 0 + -20

Reorder the terms:
20 + -20 + -8x + x2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + -8x + x2 = 0 + -20
-8x + x2 = 0 + -20

Combine like terms: 0 + -20 = -20
-8x + x2 = -20

The x term is -8x.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8x + 16 + x2 = -20 + 16

Reorder the terms:
16 + -8x + x2 = -20 + 16

Combine like terms: -20 + 16 = -4
16 + -8x + x2 = -4

Factor a perfect square on the left side:
(x + -4)(x + -4) = -4

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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